SOLUTION: an aircraft carrier left port 53 and traveled west an an average speed of 10km/h. a submarine left three hours later and traveled in the opposite direction with an average speed of

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Question 453354: an aircraft carrier left port 53 and traveled west an an average speed of 10km/h. a submarine left three hours later and traveled in the opposite direction with an average speed of 10km/h. how long does the submarine need to travel before the ships are 150km apart?
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
3x10 kph+20x=150
20x=120
x=6
It will be 6 hours before the two craft are 150 km apart..