SOLUTION: How many pounds of candy worth $0.50 per pound and how many pounds of peanuts worth $0.90 per pound must be mixed to get a mixture of 64 pounds worth $0.60 per pound? I need to wri
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Question 45317This question is from textbook Intermediate Algebra
: How many pounds of candy worth $0.50 per pound and how many pounds of peanuts worth $0.90 per pound must be mixed to get a mixture of 64 pounds worth $0.60 per pound? I need to write the equation and solve it.
Gracias.
Lydia Alejandro. This question is from textbook Intermediate Algebra
You can put this solution on YOUR website! Let the pounds of candy to be mixed be x pounds and the pounds of peanut to be mixed be y pounds.
Now the total pounds of the mixture is 64 as stated in the problem.
Hence the first equation we have is x + y = 64,
can also be written as x = 64 - y
Now candy is worth $0.50 / pound, if there are x pounds of candy then they will be worth 0.50 times x = 0.5x dollars
Similarly, peanut is worth $0.90 / pound, hence y pounds of peanut will be worth 0.9y dollars.
The problem states the total mixture is worth $0.6 / pound and weighs 64 lbs.
Hence the total mixture amounts to 0.6 * 64 = $38.4
Since the mixture is x pounds of candy and y pounds of peanut, we can equate the total dollar values as:
0.5x + 0.9y = 0.6 (64) = 38.4 (this is the second equation)
But we know x = 64 - y (from the first equation)
Therefore substituting this value of x in the second equation,
0.5(64 - y) + 0.9y = 38.4
32 - 0.5y + 0.9y = 38.4
0.4y = 6.4
y = 16
x = 64 - y = 64 - 16 = 48
(If you have any questions on the solution you can send me your queries at tutmath@gmail.com)
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