SOLUTION: I am having a problem factoring this one 14a^(2)-45a-14

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Question 452963: I am having a problem factoring this one 14a^(2)-45a-14
Found 3 solutions by mananth, ikleyn, MathTherapy:
Answer by mananth(16949)   (Show Source):
You can put this solution on YOUR website!
Find the roots of the equation by quadratic formula

a= 14 ,b= -45 ,c= -14

b^2-4ac= 2025 + 784
b^2-4ac= 2809
=53

x1=(45+ 53)/28
x1=3.5
x2=(45-53)/28
x2= -0.29

Answer by ikleyn(53617)   (Show Source):
You can put this solution on YOUR website!
.
I am having a problem factoring this one 14a^2-45a-14.
~~~~~~~~~~~~~~~~~~~~~~~~

        The standard treatment of this problem and many other similar problems is to find
        the roots of a polynomial and then to decompose the polynomial.
        @mananth in his post started the job, but not completed it, so I came to do everything
        from the beginning to the end.

Find the roots of the given polynomial using the quadratic formula d = b^2 - 4ac = 45^2 - 4*14*(-14) = 2809 = = = = = ; = = = = = . Therefore, the decomposition of our polynomial is 14a^2 - 45a - 14 = = (2a-7)*(7a+2). ANSWER. 14a^2 - 45a - 14 = (2a-7)*(7a+2).

Solved.

Answer by MathTherapy(10719)   (Show Source):
You can put this solution on YOUR website!

I am having a problem factoring this one 14a^(2)-45a-14 Use the "ac" method ---- Replacing - 45a with - 49a + 4a