Question 452262: I hope this is a linear equation and that someone can help me convert it from words to and equation and graph.
I need to illustrate the decline in the herring population over the years and estimate what will happen if the trend continues. I've spent all day researching the information and now I have no idea how to put it together, or even if it belongs together :0
Every year the herring returning to the Stonybrook Run to spawn is declining as overfishing, water pollution, and loss of habit takes a toll on their numbers.
In 2000, you could count 100 herring go through the run in 1 minute, but by 2005, it took 5 minutes to count the same number.
The count in 2010 took 10 minutes to count the 100 fish. If the trend continues how long will it take count 100 herring in 2015?
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! Create a table of data:
year time
2000 1
2005 5
2010 10
.
Plot the above three points on graph paper.
Because the dots appears to be in a straight line, you can assume it is linear.
.
Determine slope:
m = (y2-y1)/(x2-x1) using first and last points
m = (10-1)/(2010-2000)
m = (9)/(10)
m = 9/10
.
using the slope above and one point (2000,1)
plug it into the "point-slope" form:
y - y1 = m(x - x1)
y - 1 = (9/10)(x - 2000)
y - 1 = (9/10)x - (9/10)2000
y - 1 = (9/10)x - (9)200
y - 1 = (9/10)x - 1800
y = (9/10)x - 1801 (this is your equation)
.
For, 2015:
y = (9/10)x - 1801
y = (9/10)2015 - 1801
y = (9)201.5 - 1801
y = (9)201.5 - 1801
y = 1813.5 - 1801
y = 12.5 minutes
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