SOLUTION: The U.S. Customs Service conducted a random check of Miami longshoremen and found that 36 of 50 had arrest records. (a) Construct a 90 percent confidence interval for the true prop
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Question 452221: The U.S. Customs Service conducted a random check of Miami longshoremen and found that 36 of 50 had arrest records. (a) Construct a 90 percent confidence interval for the true proportion. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The U.S. Customs Service conducted a random check of Miami longshoremen and found that 36 of 50 had arrest records. (a) Construct a 90 percent confidence interval for the true proportion.
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sample proportion: 36/50 = 0.72
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SE = 1.645*sqrt[0.72*0.28/50] = 0.104
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90% CI: 0.72-0.104 < p < 0.72+0.104
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Cheers,
Stan H.
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