SOLUTION: i am having troubles with solving the systems of equations in substitution. how do you solve the equation x-2y=0 and 4x-3y=15 in ordered pair form, (x,y)?
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Question 451984: i am having troubles with solving the systems of equations in substitution. how do you solve the equation x-2y=0 and 4x-3y=15 in ordered pair form, (x,y)? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! x-2y=0 .............1
-3y=15-4x---------2
/-3 =
y=-5+1.33x
Plug the value of y in (1)
x-2(-5+ 1.33x)= 0
x+10-2.67x=0
x-2.67x =0-10
-1.67x=-10
/-1.67
x=6
Plug the value of x in (1)
x-2y=0
1*6-2y= 0
6-2y=0
-2y=-6
/-2
y=3
(2,3)
