SOLUTION: The owner of a home decorating shop wants to mix dried corn for $6lb., dried cranberries selling for $5/1b. and flour selling for $3 lb. to get 10 pounds of a mixture that would se

Algebra ->  Customizable Word Problem Solvers  -> Evaluation -> SOLUTION: The owner of a home decorating shop wants to mix dried corn for $6lb., dried cranberries selling for $5/1b. and flour selling for $3 lb. to get 10 pounds of a mixture that would se      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 451927: The owner of a home decorating shop wants to mix dried corn for $6lb., dried cranberries selling for $5/1b. and flour selling for $3 lb. to get 10 pounds of a mixture that would sell for $3.80/lb. he wants to use twice as many pounds of dries corn as drive cranberries. how many pounds of each of the 3 ingredients should he use?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The owner of a home decorating shop wants to mix dried corn for $6 lb., dried cranberries selling for $5/1b. and flour selling for $3 lb. to get 10 pounds of a mixture that would sell for $3.80/lb. he wants to use twice as many pounds of dried corn as dried cranberries. how many pounds of each of the 3 ingredients should he use?
-----------------
Quantity Eq: r + c + f = 10 lbs.
Quantity Eq: r -2c + 0 = 0 lbs.
Value Eq::: 6r +5c +3f = 3.8*10
-----------------
I ran a matrix program on my TI-84 and got:
corn = 2 lbs
cranberries = 1 lbs
flour = 7 lbs
====================
Cheers,
Stan H.
===============