SOLUTION: the bout sails from A to B on a bearing 168 degree and then from B to C on a bearing of 078 degree. AB=BC
a) show that angle ABC=90
b)work out the bearing of C from A
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-> SOLUTION: the bout sails from A to B on a bearing 168 degree and then from B to C on a bearing of 078 degree. AB=BC
a) show that angle ABC=90
b)work out the bearing of C from A
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Question 451617: the bout sails from A to B on a bearing 168 degree and then from B to C on a bearing of 078 degree. AB=BC
a) show that angle ABC=90
b)work out the bearing of C from A Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! the bout sails from A to B on a bearing 168 degree and then from B to C on a bearing of 078 degree. AB=BC
a) show that angle ABC=90
160 = 078 = 90º
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b)work out the bearing of C from A
From A to C = 168 - 45 = 123
From C to A = 123 + 180 = 303
