Question 451604: two consecutive numbers are squared and then added to gether to get the result of 113. What is the starting formula? Found 3 solutions by nerdybill, Alan3354, pedjajov:Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! two consecutive numbers are squared and then added to gether to get the result of 113. What is the starting formula?
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Let x = first consecutive number
then
x+1 = second consecutive number
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x^2 + (x+1)^2 = 113 (you can probably leave it like this)
x^2 + (x+1)(x+1) = 113
x^2 + (x^2+x+x+1) = 113
x^2 + (x^2+2x+1) = 113
2x^2+2x+1 = 113
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