SOLUTION: Debbie leaves the house walking at a rate of 3 miles per hour. After 10 minutes, her mother realizes that Debbie has forgotten her homework and leaves the house riding a bicycle at

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Debbie leaves the house walking at a rate of 3 miles per hour. After 10 minutes, her mother realizes that Debbie has forgotten her homework and leaves the house riding a bicycle at      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 451534: Debbie leaves the house walking at a rate of 3 miles per hour. After 10 minutes, her mother realizes that Debbie has forgotten her homework and leaves the house riding a bicycle at a rate of 10 miles per hour. How many minutes after Debbie initially left the house will her mother catch up to her?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Debbie leaves the house walking at a rate of 3 miles per hour.
After 10 minutes, her mother realizes that Debbie has forgotten her homework and
leaves the house riding a bicycle at a rate of 10 miles per hour.
How many minutes after Debbie initially left the house will her mother catch up to her?
:
Convert 10 min to 1%2F6 hrs
:
Let t = D's travel time (hrs) when Mom catches her
then
(t - 1%2F6) = Mom's travel time
:
When Mom catches D, they will have traveled the same distance.
Write a distance equation; dist = speed*time
10(t-1%2F6) = 3t
10t - 10%2F6 = 3t
10t - 3t = 10%2F6
7t = 10%2F6
multiply both sides by6
6*7t = 10
42t = 10
t = 10%2F42
t = .2381 * 60 = 14.3 min is D's travel time, when Mom catches her.
:
: