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Question 451510: Answer this quesion four brother were born in two year intervals, the sum of their ages is 36. Find the age of each.
Answer by pedjajov(51)   (Show Source):
You can put this solution on YOUR website! Let's mark the age of each brother with B1, B2, B3, B4
B1 = x - youngest brother's age is x years
B2 = x + 2 - next brother is 2 years older then the youngest
B3 = x + 4 - next brother is 2 years older than the previous brother
B4 = x + 6 - next brother is 2 years older than the previous brother
Sum of all their ages is 36:
B1 + B2 + B3 + B4 = 36
x + (x + 2) + (x + 4) + (x + 6) = 36
x + x + 2 + x + 4 + x +6 = 36
4x + 12 = 36
4x = 36 -12 = 24
x = 24/4
x = 6
Now when we know the age of the youngest brother we can find ages of all 4:
B1 = 6
B2 = 8
B3 = 10
B4 = 12
Check: 6 + 8 + 10 + 12 = 36
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