Question 451491: I submitted this once already with no responce maybe I had it in the wrong category?
Find the x and y intercepts and one other point of the line 2x-y= -7
Found 2 solutions by algebrahouse.com, stanbon:
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! To find the x-intercept, put 0 in for y:
2x - y = -7
2x - 0 = -7 {put 0 in for y}
2x = -7 {subtracted 0}
x = -7/2 {divided both sides by 2}
(-7/2 , 0) are the coordinates of the x-intercept
To find the y-intercept, put 0 in for x:
2x - y = -7
2(0) - y = -7 {put 0 in for x}
-y = -7 {multiplied 2 by 0}
y = 7 {divided both sides by -1}
(0,7) are the coordinates of the y-intercept
To find another point, put any number in for x or y
2x - y = -7
2x - 1 = -7 {put 1 in for y}
2x = -6 {added 1 to both sides}
x = -3 {divided both sides by 2}
(-3,1) are the coordinates of another point on the line
www.algebrahouse.com
Answer by stanbon(75887)  (Show Source):
You can put this solution on YOUR website! Find the x and y intercepts and one other point of the line 2x-y= -7
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x-intercept = ?
Let y = 0, then 2x = -7; x = -7/2 = -3.5
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y-intercept = ?
Let x = 0, then -y = -7; y = 7
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One other point:
Solve for "y":
y = 2x+7
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Let x = 2, then y = 2*2+7 = 11
giving you point (2,11)
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Cheers,
Stan H.
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