SOLUTION: How would one go about answering an equation like: x * log(3) - x = ln(7) ?

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Question 451262: How would one go about answering an equation like: x * log(3) - x = ln(7) ?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
How would one go about answering an equation like: x * log(3) - x = ln(7) ?
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log(3) and ln(7) are constants.
x * log(3) - x = ln(7)
x*(log(3) - 1) = ln(7)
x = ln(7)/(log(3) - 1)
x =~ -3.72153