Question 451136: Solve: 25^log5^x=5
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Solve: 25^log5^x=5
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25^log5^x=5
25=5^2
5^2^log5^x=5
5^2log5^x=5^1
2log5^x=1
log5^x=1/2
convert to exponential form, (base(10) raised to log of number(1/2)=number(5^x)
10^(1/2)=5^x
3.1623=5^x
(take logs of both sides)
xlog5=log(3.1623)
x=log(3.1623)/log5
x=.7153
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Check:
25^log5^x
25^log5^.7153=4.999...
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