SOLUTION: Find two consecutive odd integers such that the sum of their squares is 74.

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Question 450847: Find two consecutive odd integers such that the sum of their squares is 74.
Found 2 solutions by solver91311, MathLover1:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Let represent the first odd integer. Then the second odd integer is .

The first one squared is:

The second one squared is:

The sum is:

And the sum is equal to 74, so:



Divide by 2:



Factor and solve the quadratic.

John

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Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

two consecutive odd integers such that the sum of their squares is 74
Assign variables :
Let x = first odd integer, and
x+%2B+2 = second odd integer

the sum of their squares is x%5E2%2B%28x%2B2%29%5E2=74....solve for x

x%5E2%2Bx%5E2%2B4x%2B4=74

2x%5E2%2B4x%2B4-74=0

2x%5E2%2B4x-70=0...use quadratic formula

x+=+%28-4+%2B-+sqrt%28+4%5E2-4%2A2%2A%28-70%29+%29%29%2F%282%2A2%29+

x+=+%28-4+%2B-+sqrt%28+16%2B560%29%29%2F4+

x+=+%28-4+%2B-+sqrt%28576%29%29%2F4+

x+=+%28-4+%2B-24%29%2F4+
solutions:
x+=+%28-4+%2B24%29%2F4+
x+=+20%2F4+
x+=+5+
or

x+=+%28-4+-24%29%2F4+
x+=+-28%2F4+
x+=+-7+

now find second odd integer
x%2B2=5%2B2=7 or x%2B2=-7%2B2=-5

so, your numbers are:

5+ and 7
or
-7 and -5