SOLUTION: Solve each of the following systems by addition. If a unique solution does not exist, state whether the system is consistent or dependent. 2). x-y = 8 x + y = 2 16). 2x-y=

Algebra ->  Linear-equations -> SOLUTION: Solve each of the following systems by addition. If a unique solution does not exist, state whether the system is consistent or dependent. 2). x-y = 8 x + y = 2 16). 2x-y=      Log On


   

Question 45075: Solve each of the following systems by addition. If a unique solution does not exist, state whether the system is consistent or dependent.
2). x-y = 8
x + y = 2
16). 2x-y=4
2x-y=6
32). 3x + 4y =0
5x - 3y = -29
42). 3x + 3y =1
2x + 4y =2
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
ALL ARE OF SIMILAR TYPE.PLEASE TRY YOUR SELF BASED ON TWO EXAMPLES WORKED OUT BELOW
Solve each of the following systems by addition. If a unique solution does not exist, state whether the system is consistent or dependent.
2). x-y = 8
x + y = 2
ADDING THE ABOVE EQNS.
2X=8+2=10
X=10/2=5
5+Y=2
Y=2-5=-3



16). 2x-y=4
2x-y=6
SUBTRACTING EQN.II FROM EQN.I
0=4-6=-2...NOT POSSIBLE
HENCE NO SOLUTION
THE 2 EQNS.ARE DEPENDENT AND INCONSISTENT
32). 3x + 4y =0
5x - 3y = -29
42). 3x + 3y =1
2x + 4y =2