SOLUTION: Solve the logarithmic equation. Be sure to reject any value of x that produces the logarithmic of a negative number or the logarithm of 0.
{{{log(3,x)+log(3) (4x-9)=2}}}
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-> SOLUTION: Solve the logarithmic equation. Be sure to reject any value of x that produces the logarithmic of a negative number or the logarithm of 0.
{{{log(3,x)+log(3) (4x-9)=2}}}
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Question 450523: Solve the logarithmic equation. Be sure to reject any value of x that produces the logarithmic of a negative number or the logarithm of 0.
[The 3 next to the second log is suppose to be a base.]
Type an integer or a fraction. Simplify your answer. Use a comma to seperate answers if necessary. Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! log(3,x)+log(3) (4x-9)=2
3^log(3,x)+3^log(3) (4x-9)=3^2
x(4x-9)=9
4x^2-9x-9=0
(x-3)(4x+3)=0
x=3
.
Ed
