Question 450039: A jar contains 4 white chips, 5 purple chips, and 1 black chip. Chips are selected randomly one at a time, and are not replaced. Find the probability of the following.
a) purple chip then black
b) black chip then white chip
c) 2 purple chips
d) white chip, then purple chip, then black chip
e) 3 white chips
f) black chip, then white chip, then red chip
Found 2 solutions by ewatrrr, solver91311:
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi,
10 chips in all (4-w,5-p,1-b)
Chips are selected randomly one at a time, and are "not replaced".
Find the probability of the following.
a) purple chip then black = 5/10*1/9
b) black chip then white chip = 1/10*4/9
c) 2 purple chips = 5*10*4/9
d) white chip, then purple chip, then black chip = 4/10*5*9*1/8
e) 3 white chips = 4/10*3/9*2/8
f) black chip, then white chip, then red chip = 0 (no red chips)
Answer by solver91311(24713)  (Show Source):
You can put this solution on YOUR website!
a) There are 5 purple chips out of 10 total chips, so the probability of picking a purple chip on the first draw is 1/2. Then, given a purple was picked on the first draw with no replacement, there is 1 black chip out of 9 remaining chips, so 1/9. 1/2 times 1/9 = 1/18.
Sorry, you only get one problem answered per post.
John
My calculator said it, I believe it, that settles it
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