SOLUTION: Conrad can jog to Chris's house in 10 minutes. Chris can ride her bike to Conrad's house in 6 minutes. If they start from their houses at the same time, in how many minutes do they

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Question 449557: Conrad can jog to Chris's house in 10 minutes. Chris can ride her bike to Conrad's house in 6 minutes. If they start from their houses at the same time, in how many minutes do they meet?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
They will each travel for the same amount of time
Let +d+ = the distance between their houses
Let +t+ = time for them to meet
Conrad's rate = ++d%2F10+
Chris's rate = +d%2F6+
---------------------
For Conrad:
Conrad's distance = +%28d%2F10%29%2At+
Chris's distance = +%28d%2F6%29%2At+
The sum of the distances is d
+d+=+%28d%2F10%29%2At+%2B+%28d%2F6%29%2At+
Divide both sides by d
+1+=+%281%2F10%29%2At+%2B+%281%2F6%29%2At+
+60+=+6t+%2B+10t+
+16t+=+60+
+t+=+3.75+
They will meet in 3 minutes and 45 seconds
check:
Conrad's distance = +%28d%2F10%29%2At+=+%28d%2F10%29%2A3.75+
Conrad's distance = +.375d+
Chris's distance = +%28d%2F6%29%2At+=+%28d%2F6%29%2A3.75+
Chris's distance = +.625d+
+d+=+.375d+%2B+.625d+
+d+=+d+
OK