SOLUTION: Find all solutions of the equation in the interval [0,2pi].
(2cosθ+sqrt3)(cscθ+1)=0
Write your answer in radians in terms of pi .
If there is more than one solutio
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-> SOLUTION: Find all solutions of the equation in the interval [0,2pi].
(2cosθ+sqrt3)(cscθ+1)=0
Write your answer in radians in terms of pi .
If there is more than one solutio
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Question 449364: Find all solutions of the equation in the interval [0,2pi].
(2cosθ+sqrt3)(cscθ+1)=0
Write your answer in radians in terms of pi .
If there is more than one solution, separate them with commas. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Find all solutions of the equation in the interval [0,2pi].
(2cosθ+sqrt3)(cscθ+1)=0
..
(2cosx+√3)(cscx+1)=0
cscx+1=0
cscx=-1
x=3π/2 radians
2cosx+√3=0
cosx=-√3/2
x=5π/6 & 7π/6 radians (cosine negative in quadrants II & III)
solutions:
x=3π/2, 5π/6, and 7π/6 radians
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