SOLUTION: 3y squared + 14y = 5 How do I compute this? Thanks for your help

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Question 449247: 3y squared + 14y = 5 How do I compute this? Thanks for your help
Found 2 solutions by poliphob3.14, MathLover1:
Answer by poliphob3.14(115) About Me  (Show Source):
You can put this solution on YOUR website!
First set the equation to zero:3y%5E2%2B14y-5=0, solve the equation by factoring
3%283y-1%29%283y%2B15%29=0.Set each factor to zero: 3y-1=0=> y=1/3 and 3y+15=0=>
y=-5. The roots are:{ -5, 1/3 }.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
3y%5E2+%2B+14y+=+5....use quadratic formula to solve for y
3y%5E2+%2B+14y+-+5+=+0
y+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+....a=3, b=14 and c=-5

y=+%28-14+%2B-+sqrt%2814%5E2-4%2A3%2A%28-5%29+%29%29%2F%282%2A3%29+

y=+%28-14+%2B-+sqrt%28196%2B60%29%29%2F6+

y=+%28-14+%2B-+sqrt%28256%29%29%2F6+

y=+%28-14+%2B-+16%29%2F6+
so, solutions are:
y=+%28-14+%2B+16%29%2F6+

y=+2%2F6+

y=+13
or

y=+%28-14+-+16%29%2F6+

y=+-30%2F6+

y=+-5

let's see it on a graph:

+graph%28+500%2C+500%2C+-10%2C10%2C+-25%2C+10%2C+3x%5E2+%2B+14x+-+5+%29+