SOLUTION: What is the center of the hyperbola? (x-2)^2 / 9 - (y-5)^2/ 4=1 Please show me how you find this I'm not learning well...Thank you.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: What is the center of the hyperbola? (x-2)^2 / 9 - (y-5)^2/ 4=1 Please show me how you find this I'm not learning well...Thank you.      Log On


   



Question 449032: What is the center of the hyperbola?
(x-2)^2 / 9 - (y-5)^2/ 4=1
Please show me how you find this I'm not learning well...Thank you.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi
%28x-2%29%5E2%2F9+-%28y-5%29%5E2%2F+4=1 Center(2,5) Vertices (-1,5) and (5,5)
See below descriptions of various conics

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2
where Pt(h,k) is the center and r is the radius
Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+
where Pt(h,k) is the center and a and b are the respective vertices distances from center.
Standard Form of an Equation of an Hyperbola opening right andd left is:
%28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 where Pt(h,k) is a center with vertices 'a' units right and left of center.
Standard Form of an Equation of an Hyperbola opening up and down is:
%28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1 where Pt(h,k) is a center with vertices 'b' units up and down from center.
Using the vertex form of a parabola opening up or down, y=a%28x-h%29%5E2+%2Bk
where(h,k) is the vertex
The standard form is %28x+-h%29%5E2+=+4p%28y+-k%29, where the focus is (h,k + p)