SOLUTION: write an equation for the conic sections 5. ellipse with center at (0,0) vertex (-4,0) and co-vertex (0,3) 6. circle with center at (-1,2) and radius 4. 7. parabola with v

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: write an equation for the conic sections 5. ellipse with center at (0,0) vertex (-4,0) and co-vertex (0,3) 6. circle with center at (-1,2) and radius 4. 7. parabola with v      Log On


   



Question 448900: write an equation for the conic sections
5. ellipse with center at (0,0) vertex (-4,0) and co-vertex (0,3)
6. circle with center at (-1,2) and radius 4.
7. parabola with vertex at (0,0) and directrix x = -3
8. hyperbola with foci at (-3,0) and (3,0) and vertices at (2,0) and (-2,0)

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi
5. ellipse with center at (0,0) vertex (-4,0) and co-vertex (0,3)
x%5E2%2F16+%2B+y%5E2%2F9+=+1
6. circle with center at (-1,2) and radius 4. %28x%2B1%29%5E2+%2B+%28y-2%29%5E2+=+16
7. parabola with vertex at (0,0) and directrix x = -3
y^2 = (3/4)x 4p = 3 p = 3/4
8. hyperbola with foci at (-3,0) and (3,0) and vertices at (2,0) and (-2,0)
y^2/4 - x^2/5 = 1 c =sqrt%284+%2B+a%5E2%29 = 3 a = sqrt%285%29

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2
where Pt(h,k) is the center and r is the radius
Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+
where Pt(h,k) is the center and a and b are the respective vertices distances from center.
Standard Form of an Equation of an Hyperbola is %28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 where Pt(h,k) is a center with vertices 'a' units right and left of center.
Standard Form of an Equation of an Hyperbola opening up and down is:
%28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1 where Pt(h,k) is a center with vertices 'b' units up and down from center.
Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex
The standard form is %28x+-h%29%5E2+=+4p%28y+-k%29, where the focus is (h,k + p)