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Question 448700: Find the center and radius of the circle:
x^2+y^2-6x+2y+6=0
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find the center and radius of the circle:
x^2+y^2-6x+2y+6=0
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Complete the square on the x-terms and on the y-terms:
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x^2-6x+9 + y^2+2y+1 = -6+9+1
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(x-3)^2 + (y+1)^2 = 4
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Center: (3,-1)
Radius: sqrt(4) = 2
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Cheers,
Stan H.
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