SOLUTION: what is the center of this ellipse? x2+4y2+12x-32y+96=0

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Question 448544: what is the center of this ellipse? x2+4y2+12x-32y+96=0
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

 Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+where Pt(h,k) is the center 

and a and b  are the respective vertices distances from center.

x^2+4y^2+12x-32y+96=0 

 (x+6)^2 - 36  + 4(y-4)^2 - 4*16  + 96  = 0   

 (x+6)^2 + 4(y-4)^2  = 4

+%28x%2B6%29%5E2%2F4+%2B+%28y-4%29%5E2%2F1++=+1+  Center (-6,4)