SOLUTION: sin(Arccos(-2/5)
I need help finding the wrapping function of (-2/5) I am not quite sure on how to find the denominator of 5. Our teacher only taught us 2,3,4,6,8, and 12. Thank
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-> SOLUTION: sin(Arccos(-2/5)
I need help finding the wrapping function of (-2/5) I am not quite sure on how to find the denominator of 5. Our teacher only taught us 2,3,4,6,8, and 12. Thank
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Question 448516: sin(Arccos(-2/5)
I need help finding the wrapping function of (-2/5) I am not quite sure on how to find the denominator of 5. Our teacher only taught us 2,3,4,6,8, and 12. Thank you for your help! Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! sin(Arccos(-2/5))
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The point is on a circle of radius 5, and the x value is -2
It's the 2nd quadrant (the principal value).
Find the y value.
y = sqrt(21)
