SOLUTION: The question I have is this. C = W^2L^3 ------- 24T^2 I am trying to solve for "W". The solution the book gives is W= "the square root of both the numerator and d

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The question I have is this. C = W^2L^3 ------- 24T^2 I am trying to solve for "W". The solution the book gives is W= "the square root of both the numerator and d      Log On


   

Question 4485: The question I have is this.
C = W^2L^3
-------
24T^2
I am trying to solve for "W".
The solution the book gives is W= "the square root of both the numerator and denominator"
(CL^3)
-------
(24T^2)
I understand that to just get "W" from W^2 you have to take the square root of it and what you do to one side you must do to the other, but how does "C" and "W" both stay in the numerator on both sides if you must use the reciprocol to move them on the different sides of the equasion?
Found 2 solutions by longjonsilver, jk12312:
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
if you have C+=+%28W%5E2L%5E3%29%2F%2824T%5E2%29, then rearranging for W, gives:

W%5E2+=+%2824CT%5E2%29%2F%28L%5E3%29

then W+=+%2Bsqrt%28%2824CT%5E2%29%2F%28L%5E3%29%29 OR W+=+-sqrt%28%2824CT%5E2%29%2F%28L%5E3%29%29

Remember, taking a square root ALWAYS generates 2 answers!

So, i have no idea what your book is quoting.

jon

Answer by jk12312(1) About Me  (Show Source):