SOLUTION: 1. 5*7^0 = 2. 1/4-^2 = ` 3. (1/4) ^-1/2 = 4. (bm)^-3= 5. y^-5/y^-2 = 6. (-243)^3/5= 7.-16^1/2= 8. express in logarithmic form x^y=P 9.express in expone

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: 1. 5*7^0 = 2. 1/4-^2 = ` 3. (1/4) ^-1/2 = 4. (bm)^-3= 5. y^-5/y^-2 = 6. (-243)^3/5= 7.-16^1/2= 8. express in logarithmic form x^y=P 9.express in expone      Log On


   



Question 448406: 1. 5*7^0 =
2. 1/4-^2 =
`
3. (1/4) ^-1/2 =
4. (bm)^-3=
5. y^-5/y^-2 =
6. (-243)^3/5=
7.-16^1/2=
8. express in logarithmic form
x^y=P
9.express in exponential form
log b M=y
10. solve for x without tables
x=log e ^e
x=log e 1
x=log e sqrt (e)

11. use matrix methods to solve
x+4y=8
2x+y=9
(4)+(8)
(7) (2)=

(1 8)(7 6)
(0 7)(7 4)=

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
1. 5*7^0 = 5 Any number >0 to the 0 power equals 1.