SOLUTION: the length and width of a rectangle are 6 m and 4 m. when eacch dimension is increased by the same amount, the area of the new rectangle is 50. find the dimensions of the new recta

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: the length and width of a rectangle are 6 m and 4 m. when eacch dimension is increased by the same amount, the area of the new rectangle is 50. find the dimensions of the new recta      Log On

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Question 448353: the length and width of a rectangle are 6 m and 4 m. when eacch dimension is increased by the same amount, the area of the new rectangle is 50. find the dimensions of the new rectangle
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
length =6
width = 4
increased by x
new length = 6+x
new width = 4+x
Area = (6+x)(4+x)
50 = 24+10x+x^2
x^2+10x-26=0
Find the roots of the equation by quadratic formula
a= 1 ,b= 10 ,c= -26

b^2-4ac=100 + 104
b^2-4ac=204
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-12%2Bsqrt%2824%29%29%2F%2812%29
x1=(-10 +14.28)/2
x1=2.14
x2=(-10 -14.28)/2
x2= -12.14
ignore negative value.
x= 2.14, add this to old length
new length = 8.14
new width = 6.14