Question 448342: Solve for x: log base 4 (x^2 + 3x) - log base 4 (x +5) = 1
I know that I am supposed to do this; 4^1 = x^2 + 3x
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x +5
HOwever I am not entirely sure that this is the correct method Answer by jim_thompson5910(35256) (Show Source):