SOLUTION: 2x^2 - 25 = 0 Can you tell me how MANY solutions exist for this equation? (Use the discriminant)

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Question 448327: 2x^2 - 25 = 0
Can you tell me how MANY solutions exist for this equation? (Use the discriminant)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
From 2x%5E2-25 we can see that a=2, b=0, and c=-25


D=b%5E2-4ac Start with the discriminant formula.


D=%280%29%5E2-4%282%29%28-25%29 Plug in a=2, b=0, and c=-25


D=0-4%282%29%28-25%29 Square 0 to get 0


D=0--200 Multiply 4%282%29%28-25%29 to get %288%29%28-25%29=-200


D=0%2B200 Rewrite D=0--200 as D=0%2B200


D=200 Add 0 to 200 to get 200


So the discriminant is D=200


Since the discriminant is greater than zero, this means that there are two real solutions. These solutions are distinct (ie different from one another).