SOLUTION: The graph of the equation below is a circle. What is the length of the radius of the circle?(x - 6)2 + (y + 5)2 = 152

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: The graph of the equation below is a circle. What is the length of the radius of the circle?(x - 6)2 + (y + 5)2 = 152      Log On


   

Question 448264: The graph of the equation below is a circle. What is the length of the radius of the circle?(x - 6)2 + (y + 5)2 = 152
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
The equation is in the same form as that of a circle (x-h)^2 + (y-k)^2 = r^2, with r^2 = 152. This implies that r = sqrt(152).