SOLUTION: How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to form an alloy containing 78% nickel?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to form an alloy containing 78% nickel?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 448225: How many mg of a metal containing 45% nickel must be combined with 6 mg of pure nickel to form an alloy containing 78% nickel?
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
.45n+6=.78(n+6)
.45n+6=.78n+4.68
.33n=1.32
n=1.32/.33=4
You need 4 mg of 45% nickel to complete your alloy..