Question 448191: y= 2tan(1/2)*with a theta sign*
the problem tells me to graph it
thanks :)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! y= 2tan(1/2)*with a theta sign*
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let x=angle=theta
Graph for one period
y= 2tan(x/2)
Standard form for tan function: y=tan(Bx-C), where period=π/B, phase shift=C/B
For given tan function:
B=1/2
Period=π/B=π/(1/2)=2π
1/4 period=2π/4=π/2
Phase-shift = 0
I don't have the means to graph it for you, but I can show you how as follows:
On the x-axis place a tick mark starting from -π, followed by 4 more tick marks spaced 1/4 period apart, that is, you will now have tick marks at -π, –π/2, 0, π/2,and π which covers one full period.
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At x=-π
y=2tan(-π/2)=undefined
so, at this point you will have asymptote x=-π
At next mark, x=-π/2
y=2tan(-π/4)=-2
at x=0
y=2tan(0)=0
at x=π/2
y=2tan(π/4)=2
at x=π
y=2tan(π/2)= undefined
so at this point you will have an asymptote x=π
Now you have the following points with which you can graph the given function for one
period:
(-π,-∞),(-π/2,-2), (0,0), (π/2,2) and (π,∞)
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