SOLUTION: For f(x)=1/x^2-2x-8, find the interval(s) where f(x)<0. Thank you.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: For f(x)=1/x^2-2x-8, find the interval(s) where f(x)<0. Thank you.      Log On


   

Question 44813This question is from textbook
: For f(x)=1/x^2-2x-8, find the interval(s) where f(x)<0.
Thank you. This question is from textbook

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) = 1/(x^2 - 2x - 8)
0 > 1/(x^2 - 2x - 8)
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+1%2F%28x%5E2+-+2x+-+8%29+%29+
(-2,+infinity)U(-infinity,4)