SOLUTION: i need your help... can you graph this equation? y=-(x-4)^2+3
*state weather the graph opens upward or downwards?
*is the vertex of the graph a maximum or minimum point?
*find t
Algebra ->
Inequalities
-> SOLUTION: i need your help... can you graph this equation? y=-(x-4)^2+3
*state weather the graph opens upward or downwards?
*is the vertex of the graph a maximum or minimum point?
*find t
Log On
Question 447948: i need your help... can you graph this equation? y=-(x-4)^2+3
*state weather the graph opens upward or downwards?
*is the vertex of the graph a maximum or minimum point?
*find the vertex of the graph of the functon?
*what is the axis of symmetry?
*identify the transformation of the graph (how did you mave the parabola)? Found 2 solutions by stanbon, Gogonati:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! i need your help... can you graph this equation? y=-(x-4)^2+3
*state weather the graph opens upward or downwards?
down because of the negative on the (x-4)^2
----------------------------------
*is the vertex of the graph a maximum or minimum point?
max because the graph goes down from the vertex.
----------------------------------
*find the vertex of the graph of the function?
Vertex: (4,3)
----------------------------------
*what is the axis of symmetry?
x = 4
----------------------------------
*identify the transformation of the graph (how did you move the parabola)?
x-4 moves the parabola to the 4 to the right.
3 moves the graph up 3 units.
===============================
Cheers,
Stan H.
You can put this solution on YOUR website! The graph is a downward parabola, its vertex is the point (4, 3) and the axis of symmetry is the line x=4.
To construct the graph we start from :1) reflect to the x-axis
,
2)shift 4 units to the right shift 3 units up
. See the graph below:
(
