Question 447885: a man goes to the bank with $6.00 and asks for change.he is given an equal number of nickels,dimes,and quarters.how many of each is he given
Found 2 solutions by mananth, ikleyn:
Answer by mananth(16949)   (Show Source):
You can put this solution on YOUR website! Let thenumber of coins be x of each.
5x+10x+25x= 600
40x=600
x= 15 nickels
15 dimes
15 quarters
15*5 + 15*10+25*15
=75+150+375
=600
Answer by ikleyn(53538)  (Show Source):
You can put this solution on YOUR website! .
A man goes to the bank with $6.00 and asks for change. He is given an equal number of nickels, dimes, and quarters.
How many of each is he given?
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It is a typical ARITHMETIC problem for 4th or 5th grade students to solve it MENTALLY by using
the grouping method.
I cannot miss this opportunity to present this solution here,
because such problems are gems for developing thinking skills in elementary school students.
Group the coins, placing one nickel, one dime and one quarter in each group.
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| According to the problem, it is possible to do so. |
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Then each such a group is worth 5 + 10 + 25 = 40 cents;
hence, the number of such groups is 600 cents divided by 40, which gives  = 15
for the number of these groups.
It gives the ANSWER: there are 15 coins of each nomination.
Solved.
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