SOLUTION: find the two-digit number whose units' digit is 5 more than its tens' digit and whose value equals 3 times the sum of these digits.

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Question 447881: find the two-digit number whose units' digit is 5 more than its tens' digit and whose value equals 3 times the sum of these digits.
Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
Let the ten's be x, then its units are x+5 and the sum of digits is x+x+5=2x+5 and the value of a number will be:10x+x+5=11x+5. Since its value equals 3 times the sum of the digits we write the equation:
11x%2B5=3%282x%2B5%29=>5x=10=>x=2.The units are 2+5=7.
Answer: The two digit number is 27.