SOLUTION: assume that the length of a typical televised baseball game, including all the commercials timeouts, is normally distributed with mean 2.45 hours and standard deviation 0.37 hours.

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Question 447790: assume that the length of a typical televised baseball game, including all the commercials timeouts, is normally distributed with mean 2.45 hours and standard deviation 0.37 hours. Consider a televised baseball game that begins at 2;00 in the afternoon. The next regularly sheduled broadcast is at 5;00. a. what is the probability that the game will cut into the next show, that is , go past 5;00.
b. If the game is over before 4:30, another half hour show can be inserted into the 4:30-5:00 slot. What is the probability of this occuring?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
assume that the length of a typical televised baseball game, including all the commercials timeouts, is normally distributed with mean 2.45 hours and standard deviation 0.37 hours.
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Consider a televised baseball game that begins at 2;00 in the afternoon. The next regularly sheduled broadcast is at 5;00.
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a. what is the probability that the game will cut into the next show, that is , go past 5;00.
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2:00 to 5:00 is 3 hrs.
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z(3) = (3-2.45)/0.37 = 1.4865
P(x > 3) = P(z > 1.4865 = 0.0686
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b. If the game is over before 4:30, another half hour show can be inserted into the 4:30-5:00 slot. What is the probability of this occuring?
z(2.5) = (2.5-2.45)/0.37 = 0.1351
P(x <= 1.5) = P(z <= 0.1351) = normalcdf(-100,0.1351) = 0.5537
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Cheers,
Stan H.
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