SOLUTION: x^2+y^2+2x+2y+1=0

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Question 447701: x^2+y^2+2x+2y+1=0
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
it’s a circle, and the given equation is of the form
x%5E2%2By%5E2%2B2gx%2B2fy%2Bc=0

where (-g,-f) is the center

g=1 and f=1, so the center is at (-1,-1)

intercept on x+-axis=%28g%5E2-c%29%5E%281%2F2%29

substituting the values x-+intercept=0

so, it touches x axis

intercept on y-+axis=%28f%5E2-c%29%5E%281%2F2%29

substituting the values y-+intercept=0

so, it touches y axis


Solved by pluggable solver: PLOT any circle and describe it

Diameter: d+=+2r+=+2%2A1+=+2.
Area: area+=+pi%5Cr%5E2+=+pi%2A1%5E2+=+3.1415926939894
Perimeter: perimeter+=+2%5Cpi%5Cr+=+2%5Cpi%2A1+=+6.28318538797879