Question 447687: A coffee company uses Columbian and Brazilian beans to make two blends of coffee, robust and mild. A pound of the robust blend uses 12 ounces of Columbian and 4 ounces of Brazilian beans. A pound of the mild uses 6 ounces of Columbian and 10 ounces of Brazilian beans. They have 105600 ounces of the Columbian beans and 84480 ounces of the Brazilian beans. How many pounds of each blend can they make to use all available beans?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A coffee company uses Columbian and Brazilian beans to make two blends of coffee, robust and mild.
A pound of the robust blend uses 12 ounces of Columbian and 4 ounces of Brazilian beans.
A pound of the mild uses 6 ounces of Columbian and 10 ounces of Brazilian beans.
They have 105600 ounces of the Columbian beans and 84480 ounces of the Brazilian beans.
How many pounds of each blend can they make to use all available beans?
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Columbian Equation: 12r + 6m = 105600
Brazilian Equation: 4r + 10m= 84480
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Multiply thru Brazilian by 3:
12r + 30m = 3*84480
12r + 6m = 105600
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Subtract and solve for "m":
24m = 147840
m = 6160 oz = 385 pounds of mild coffee
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Solve for "r":
4r + 10m = 84480
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4r + 10*385 = 84480
4r = 80630
r = 20157.5 oz = 1259.84 pounds of robust coffee
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Cheers,
Stan H.
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