SOLUTION: A mason can lay the bricks in a sidewalk in 14 hours. The mason's apprentice requires 22 hours to do the same job. After working together for 3 hours, the mason leaves for another

Algebra ->  Rate-of-work-word-problems -> SOLUTION: A mason can lay the bricks in a sidewalk in 14 hours. The mason's apprentice requires 22 hours to do the same job. After working together for 3 hours, the mason leaves for another       Log On


   

Question 447510: A mason can lay the bricks in a sidewalk in 14 hours. The mason's apprentice requires 22 hours to do the same job. After working together for 3 hours, the mason leaves for another job and the apprentice continues working. How long will it take the apprentice to complete the job?

Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
3/14+3/22=33/154+21/154=54/154=27/77 completed, 50/77 left--
x/22=50/77
1100=77x
14.28571=x
It will take the apprentice 14.28571 hours to finish the job..