SOLUTION: (3-71)(3+7i) (2-2i)(2+2i) (7-10i)(7+10i) (2+5i)(2-5i) (4+3i)(1-i) (5-7i)(1+2i) (2-5i)(2-5i)

 

Hi, 

These can be done as one would use the FOIL method: Note: i^2 = -1

F	First terms

O	Outside terms

I	Inside terms

L	Last terms

(3-7i)(3+7i) = 9+49 = 58   | SUM of the outside terms and the inside terms = 0

(2-2i)(2+2i) = 4 + 4 = 8   | SUM of the outside terms and the inside terms = 0

(7-10i)(7+10i) = 49 + 100 = 149  | SUM of the outside terms and the inside terms = 0

(2+5i)(2-5i) = 4+ 25 = 29  | SUM of the outside terms and the inside terms = 0

(4+3i)(1-i) =  4 - i + 3 = 7 -i

(5-7i)(1+2i) = 5 +3i + 14 = 19 + 3i

(2-5i)(2-5i) = 4 -20i - 25 = 29 - 20i

Note: -5i*-5i = 25*-1