SOLUTION: Solve: log5 (3x – 2) = 1 + log5 (x – 4)

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Question 447442: Solve: log5 (3x – 2) = 1 + log5 (x – 4)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
log5 (3x – 2) = 1 + log5 (x – 4)
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log5(3x-2)-log5(x-4) = 1
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log5[(3x-2)/(x-4)] = 1
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(3x-2)/(x-4) = 5
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3x-2 = 5x-20
2x = 18
x = 9
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cheers,
stan H.