SOLUTION: Hello: This is a very simple question but I am very new to algebra. 3x + 2 = x/6 I am to solve for x Thank you in advance for your help.

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Question 44733: Hello:
This is a very simple question but I am very new to algebra.
3x + 2 = x/6
I am to solve for x
Thank you in advance for your help.


Answer by adamchapman(301) About Me  (Show Source):
You can put this solution on YOUR website!
You start with this equation:
3x+%2B+2+=+x%2F6+
And you want to solve for x.
The first thing to do is to get all of your x's on one side of the equation, preferably the left hand side (purely for presentation purposes). To remove the x/6 from the right hand side, we must subtract x/6.
In an equation anything you do to one side MUST be done in the other side too. That is very important indeed.
So let's subtract x/6 FROM BIOTH SIDES:
3x%2B2-x%2F6=x%2F6-x%2F6
3x%2B2-x%2F6=0
We only want terms with an x in them on the ledt hand side of the equation, so to move the number two we must subtract 2 from both sides:
3x%2B2-x%2F6-2=0-2
3x-x%2F6=-2
To simplify the left hand side, we need to work out how many lots of x/6 make up 3x/6. To find this, multiply 3x by 6, and then put the number 6 below it:
18x%2F6-x%2F6=-2
Now that we have a six on the bottom of each term in the left hand side, wwe can add and subrtact those fractions easily:
17x%2F6=-2
Now to move the six on the bottom of the left hand side to the lright hand side, we multiply both sides by 6:
17x=-12
Now to get rid of the 17 next to the x, divide both sides by 17:
x=-12%2F17
The solution has been found.
I hope this helps.
P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk
Adam