SOLUTION: (This is all one problem)--Match each equation with the type of conic section that it is:
3x^2+4y-6x+16y+7=0
(x-1)^2/9-(y-2)^2/16=1
4x^2+4y^2-10=0
The choi
Algebra ->
Quadratic-relations-and-conic-sections
-> SOLUTION: (This is all one problem)--Match each equation with the type of conic section that it is:
3x^2+4y-6x+16y+7=0
(x-1)^2/9-(y-2)^2/16=1
4x^2+4y^2-10=0
The choi
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Question 447145: (This is all one problem)--Match each equation with the type of conic section that it is:
3x^2+4y-6x+16y+7=0
(x-1)^2/9-(y-2)^2/16=1
4x^2+4y^2-10=0
The choices are circle, ellipse, or hyperbola Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! 3x^2+4y-6x+16y+7=0 --> a parabola
(x-1)^2/9-(y-2)^2/16=1 --> hyperbola
4x^2+4y^2-10=0 --> circle
