SOLUTION: Joe has some nickels, dimes, and quarters totaling $5.30. He has 37 coins altogether and he has four more nickles than dimes and two more quarters than nickels. How many coins of e
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Question 447116: Joe has some nickels, dimes, and quarters totaling $5.30. He has 37 coins altogether and he has four more nickles than dimes and two more quarters than nickels. How many coins of each type does he have? Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! n+d+q=37
n=d+4
q=n+2=d+6
d+d+4+d+6=37
3d+10=37
3d=27
d=9
n=13
q=15
15+13+9=37
15(25)+9(10)+13(5)=375+90+65=530..