SOLUTION: 1) The legs in an isosceles right triangle measure 5 units more than twice the measure of the third side. Find the measure of each side of the triangle if the perimeter is 30.
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Question 446980: 1) The legs in an isosceles right triangle measure 5 units more than twice the measure of the third side. Find the measure of each side of the triangle if the perimeter is 30. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The legs in an isosceles right triangle measure 5 units more than twice the measure of the third side.
Find the measure of each side of the triangle if the perimeter is 30.
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I don't think this can be a "right triangle"
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Let x = the third side
then it say,"legs in an isosceles triangle measure 5 units more than twice the measure of the third side"
2x + 5 = legs of the isosceles triangle
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The three sides = 30
2(2x+5) + x = 30
4x + 10 + x = 30
4x + x = 30 - 10
5x = 20
x =
x = 4 units is the 3rd side
then
2(4) + 5 = 13 units are the other two sides
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Check: 13+13+4 = 30