SOLUTION: The product of two consecutive positive integers is 62 more than the third consecutive integer. What is the largest of the three integers?
a. 5 b. 8 c. 6 d. 10
Please show
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-> SOLUTION: The product of two consecutive positive integers is 62 more than the third consecutive integer. What is the largest of the three integers?
a. 5 b. 8 c. 6 d. 10
Please show
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Question 446717: The product of two consecutive positive integers is 62 more than the third consecutive integer. What is the largest of the three integers?
a. 5 b. 8 c. 6 d. 10
Please show me the work so I understand it. Thank you. Answer by chriswen(106) (Show Source):
You can put this solution on YOUR website! Let x be the first integer.
Let x+1 be the second integer.
Let x+2 be the third integer.
...
(x)(x+1)=x+2+62
x^2+x=x+2+62
x^2+x-x-64=0
x^2-64=0
x^2-(8)^2=0
(x+8)(x-8)=0
x=-8 or x=8
x+2= -6 or 10
...
x=10 as that is the the forth choice d.
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