SOLUTION: Solve: log12(m^2 + 73) = log12(17m + 3)

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Question 446667: Solve:
log12(m^2 + 73) = log12(17m + 3)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve:
log12(m^2 + 73) = log12(17m + 3)
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Solve:
m^2+73 = 17m+3
---
m^2-17m+70 = 0
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Use Inverse-FOIL to Factor:
m^2-10m-7m+70 = 0
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m(m-10)-7(m-10) = 0
---
(m-10)(m-7) = 0
---
m = 10 or m = 7
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Cheers,
Stan H.